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10-01-2022
Physics

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A 1,800kg rollercoaster is going down a hill with a kinetic energy of 25,000J. What is the velocity of the rollercoaster going down the hill?

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Mohsin257 Mohsin257

10-01-2022

Answer:

K. E = (mv^2)/2

Explanation:

25000= (1800× v^2)/2
25000×2= (1800× v^2)
50000=1800×v^2
50000/1800= v^2
27.77777777= V^2
5.27038=V

Velocity (V) = 5.270 m/sec

Please mark branliest if you are satisfied with the answer. Thanking you in anticipation.

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