Answer:
Let ABC be the given isosceles triangle in which AB=AC=13cm. Draw AD perpendicular from A on BC
Let BC=2x cm. Then BD=DC=x cm
In △ABD, we have
AB
2
+AD
2
+BD
2
(By pythagoras theorem)
⇒13
2
=AD
2
+x
2
⇒AD=
13
2
−x
2
=
169−x
2
Now, Area =60cm
2
⇒
2
1
(BC×AD)=60⇒
2
1
{2x×
169−x
2
}=60
⇒x
169−x
2
=60⇒x
2
(169−x
2
)=3600
⇒(x
2
−144)(x
2
−25)=0⇒x
2
=144orx
2
=25
⇒x=12orx=5
Hence, Base 2x=24cm or 10cm
solution
