[tex]\text{Given that,}\\\\\text{Diameter of the Sun} = 1.4\times 10^6 ~ \text{km}\\\\\text{Diameter of Mercury} = 5000 ~ \text{km} = 5 \times 10^3 ~ \text{km}\\\\\text{The ratio,}\\\\(1.4\times 10^6): (5\times 10^3)\\\\=\dfrac{1.4 \times 10^6}{5\times 10^3}\\\\= 0.28 \times 10^3\\\\=2.8 \times10^2[/tex]
