guilmar10m
guilmar10m guilmar10m
  • 11-01-2017
  • Mathematics
contestada

-16t^2+120=0. round to nearest hundredth

Respuesta :

Hi4801824552
Hi4801824552 Hi4801824552
  • 11-01-2017
Solution:

1) Subtract 120 from both sides
-16{t}^{2}=-120

2) Divide both sides by -16
{t}^{2}=\frac{-120}{-16}

3) Two negatives make a positive
{t}^{2}=\frac{120}{16}

4) Simplify \frac{120}{16} to \frac{15}{2}
​
{t}^{2}=\frac{15}{2}

5) Take the square root of both sides
t=\pm \sqrt{\frac{15}{2}}

6) Simplify \sqrt{\frac{15}{2}} to \frac{\sqrt{15}}{\sqrt{2}}

t=\pm \frac{\sqrt{15}}{\sqrt{2}}

Decimal Form: ±2.738613

Done!
Answer Link

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