Respuesta :

[tex]\dfrac{-7+6i}{2+3i}\times\dfrac{2-3i}{2-3i}=\dfrac{(-7+6i)(2-3i)}{(2+3i)(2-3i)}=\dfrac{4+29i}{4-9i^2}=\dfrac4{13}+\dfrac{29}{13}i[/tex]