3x - 4 + (6/x) → Option A
Step-by-step explanation:
[tex]\begin{aligned}\frac{9x^2-12x+18}{3x}&=\frac{\cancel{3}\left(3x^2-4x+6\right)}{\cancel{3}x}\\&=\frac{3x^2-4x+6}{x}\\&=\frac{3x^2}{x}-\frac{4x}{x}+\frac{6}{x}\\&=\underline{\underline{\boxed{3x-4+\frac{6}{x}}}}\end{aligned}[/tex]
