nocolebdndn nocolebdndn

06-10-2021
Mathematics

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Please please help me I will give you brainless please

Please please help me I will give you brainless please class=

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discipulus discipulus

06-10-2021

Answer:

[tex]f(x) = 2x - 1 \\ g(x) = 3x \\ h(x) = {x}^{2} + 1 \\ f( g(x)) = 2(3x) - 1 = 6x - 1 \\ f( g( - 3)) = 6( - 3) - 1 = - 19 \\ h(f(x)) = {(2x - 1)}^{2} + 1 \\ h(f(0)) = {(2(0) - 1)}^{2} + 1 \\ h(f(0)) = 2[/tex]

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