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A 600kg lifts starts from rest. It moves upward for 3.00 s with a constant acceleration until it reaches its final speed of 1.55 ms^-1 . calculate the force exerted by lift motor

Respuesta :

SOFlA

We know that,

  • Force = mass× acceleration

We already have mass so let us calculate accleration experienced by it, using first equation of motion;

  • v = u + at
  • 1.55 = 0 + a(3)
  • 1.55 = 3a
  • 1.55/3 = a
  • 0.51 m/s² = a

Put this in force's formula;

  • f = ma
  • f = 600 × 0.51
  • f = 306.00
  • f = 306 N

Therefore, the force exerted by the lift is 306 N.

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