(C)
Step-by-step explanation:
We are going to use the following conversions for this problem:
1 km = 1000 m
1 hr = 60 min
The key is to multiply the given quantity with factors such that the unwanted units cancel out, leaving only the ones we need. In this case, we need meters and minutes. The set up goes like this:
[tex]8\dfrac{\text{km}}{\text{hr}}×\dfrac{1000\:\text{m}}{1\:\text{km}}×\dfrac{1\:\text{hr}}{60\:\text{min}}[/tex]
