Answer:
D
Step-by-step explanation:
Using the rule of exponents
[tex]\frac{a^{m} }{a^{n} }[/tex] with n > m
= [tex]\frac{1}{a^{(n-m)} }[/tex] , then
[tex]\frac{4^{6} }{4^{8} }[/tex]
= [tex]\frac{1}{4^{(8-6)} }[/tex]
= [tex]\frac{1}{4^{2} }[/tex]
= [tex]\frac{1}{16}[/tex] → D
