Answer: [tex](x-3)^2 + (y-2)^2 = 16[/tex]
Explanation:
The center of this circle is point A(3,2). These coordinates are the (h,k) values.
The radius is r = 4
Plug those three items into the template [tex](x-h)^2 + (y-k)^2 = r^2[/tex] to arrive at the final answer shown above.
