2a , 1st exp= a2 + ab
= a(a+b)
2nd exp = a2-b2
= (a+b) (a-b)
HCF = (a+b)
b, 1 st exp= (a+b)2
= (a+b)(a+)
2 nd exp = a2-b2
= (a+b) ( a-b)
c, 1 st exp= (a-1)2
= (a+1) (a-1)
2nd exp= a2-1
= (a+1)(a-1)
HCF = (a-1)
d, 1st exp= (x-2)(x-3)
= x(x-3)-2(x-3)
= x2 - 3x - 2x + 6
= x2- 5x+ 6
= x2 - (3+2)x + 6
=x2 -3x-2x+ 6
= x(x-3) -2(x-3)
=(x-3)(x-2)
2 nd exp = (x+2) (x-3)
= x( x-3) + 2 (x-3)
= x2 - 3 x+ 2x -6
= x(x-3) + 2(x-3)
=(x-3) ( x+ 2)
HCF = (x-3)
