Answer:
rida22 this is the third of these you asked for...
do you need help on the steps???
the solution is using the Pythagorean theorem (a^2 + b^2 = c^2)
so distance "A" = x1-x2 which is 4 - (-4) in your problem = 8
[tex]a^2 + b^2 = c^2[/tex]
[tex]8^2 + b^2 = c^2[/tex]
"B" = y1-y2 = -5 - 2 = -7
[tex]8^2 + (-7)^2 = c^2[/tex]
64 + 49 = c^2
c^2 = 113
c = [tex]\sqrt{113}[/tex]
Step-by-step explanation:
