hannahrich4285 hannahrich4285
  • 10-07-2021
  • Mathematics
contestada

A car traveling at 4545 ft/sec decelerates at a constant 77 feet per second squared. How many feet does the car travel before coming to a complete stop

Respuesta :

MrRoyal
MrRoyal MrRoyal
  • 10-07-2021

Answer:

144.6ft

Step-by-step explanation:

Given

[tex]u = 45ft/s[/tex] --- initial velocity

[tex]a = -7ft/s^2[/tex] --- deceleration

Required

Distance traveled

To do this, we make use of:

[tex]v^2 = u^2 + 2as[/tex]

Where

[tex]v = 0[/tex] --- final velocity

So, we have:

[tex]0^2 = 45^2 - 2*7*s[/tex]

[tex]0 = 2025 - 14s[/tex]

Collect like terms

[tex]14s = 2025[/tex]

Solve for s

[tex]s = \frac{2025}{14}[/tex]

[tex]s = 144.6[/tex]

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