Respuesta :

Explanation:

[tex][{H}^{ + }] = {10}^{ - pH} [/tex]

[tex] = {10}^{ - 11.13} [/tex]

[tex] = {10}^{ (- 11 - 0.13)} [/tex]

[tex] = {10}^{ - 0.13} \times {10}^{ - 11} [/tex]

[tex] = 0.741 \times {10}^{ - 11} \frac{mol}{litre} [/tex]

HOPE IT HELPS YOU

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