Given:
The two numbers are 1280 and 630.
To find:
The HCF of the given numbers.
Solution:
First write the given numbers in prime factorization form.
[tex]1280=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 5[/tex]
[tex]630=2\cdot 3\cdot 3\cdot 5\cdot 7[/tex]
Now the product of all the common prime factors is known as the HCF of 1280 and 630.
[tex]HCF=2\cdot 5[/tex]
[tex]HCF=10[/tex]
Therefore, the HCF of 1280 and 630 is 10.
