milliespencer41
milliespencer41 milliespencer41
  • 10-12-2016
  • Mathematics
contestada

4sintheta = 5costheta

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MissPhiladelphia
MissPhiladelphia MissPhiladelphia
  • 14-12-2016
For the answer to the question above, 
Frst, divide both sides by cosθ
(this is valid because cosθ ≠ 0 for a solution to exist): 

sinθ = 5cosθ 
==> sinθ/cosθ = 5cosθ/cosθ 
==> tanθ = 5, since sinθ/cosθ = tanθ. 
I hope my answer helped you.
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