Answer:
8.324 g
Explanation:
First we convert 750.0 mL into L:
- 750.0 mL / 1000 = 0.750 L
Then we calculate the required number of moles of CaCl₂, using the definition of molarity:
- Molarity = moles / liters
- Molarity * liters = moles
- 0.100 M * 0.750 L = 0.075 mol
Finally we convert 0.075 moles of CaCl₂ into grams, using its molar mass:
- 0.075 mol * 110.98 g/mol = 8.324 g
