Seudónimo Seudónimo
  • 08-06-2021
  • Mathematics
contestada

Find a function whose graph is a parabola with vertex (1, −2) and that passes through the point (5, 14)

Respuesta :

goddessboi goddessboi
  • 08-06-2021

Answer:

[tex]f(x)=(x-1)^2-2[/tex]

Step-by-step explanation:

Equation of a parabola:

[tex]y=a(x-h)^2+k[/tex]

The vertex is given as [tex](h,k)[/tex] -> [tex](1, -2)[/tex]

Plug in both the given point and vertex to find the value of [tex]a[/tex]:

[tex]y=a(x-h)^2+k[/tex]

[tex]y=a(x-1)^2-2[/tex]

[tex]14=a(5-1)^2-2[/tex]

[tex]14=a(4)^2-2[/tex]

[tex]14=16a-2[/tex]

[tex]16=16a[/tex]

[tex]1=a[/tex]

[tex]a=1[/tex]

Therefore, the final function is [tex]f(x)=(x-1)^2-2[/tex]

See attached graph below for a visual of the function.

Ver imagen goddessboi
Answer Link

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