Answer:
[tex]x=\frac{-7+-\sqrt{37} }{6}[/tex]
Step-by-step explanation:
This (±) goes between the [tex]-7[/tex] and [tex]\sqrt{37}[/tex]
[tex]3x^{2} +7x+1=0[/tex]
[tex]ax^{2} +bx+c[/tex]
[tex]-b[/tex] ± [tex]\sqrt{b^2-4ac}[/tex]/2a
[tex]-7[/tex] ± [tex]\sqrt{(7)^2-4(3)(1)}[/tex]/2(3)
[tex]-7[/tex] ± [tex]\sqrt{49-12}[/tex]/6
[tex]-7[/tex] ± [tex]\sqrt{37}/6[/tex]
