Answer:
Step-by-step explanation:
[tex]3x^2 - 2x + 4 = 0[/tex]
a = 3, b = -2, c = 4
[tex]x = \frac{-b \pm \sqrt{b^2 - 4ac}}{2a} \\\\x = \frac{2 \pm \sqrt{2^2 - (4 \times3 \times 4} )}{2 \times 3}\\\\x = \frac{2 \pm \sqrt{4 - 48} }{6}\\\\x = \frac{2 \pm \sqrt{-44} }{6}\\\\x =\frac{2 \pm 2i \sqrt{11} }{6}\\\\x =\frac{1 + i \sqrt{11} }{3}\ , x =\frac{1 - i \sqrt{11} }{3}\\\\\\\\[/tex]
