Answer:
[tex](f \circ g)(-8) = 16[/tex]
Step-by-step explanation:
The given function are;
f(x) = x² - 3·x - 12, and g(x) = -x - 12
[tex](f \circ g)(x) = f(g(x))[/tex]
Therefore;
[tex](f \circ g)(-8) = f(g(-8))[/tex]
g(-8) = -(-8) - 12 = 8 - 12 = -4
∴ f(g(-8)) = f(-4) = (-4)² - 3×(-4) - 12 = 16
Therefore;
[tex](f \circ g)(-8) = f(g(-8)) = 16[/tex]
