Answer:
y = 0, y = [tex]\frac{1}{3}[/tex], y = [tex]\frac{3}{4}[/tex]
Step-by-step explanation:
Given
12y³ - 13y² + 3y = 0 ← factor out y from each term
y(12y² - 13y + 3) = 0
y(3y - 1)(4y - 3) = 0 ← in factored form
Equate each factor to zero and solve for y
y = 0
3y - 1 = 0 ⇒ 3y = 1 ⇒ y = [tex]\frac{1}{3}[/tex]
4y - 3 = 0 ⇒ 4y = 3 ⇒ y = [tex]\frac{3}{4}[/tex]
