supremepersiancat
supremepersiancat supremepersiancat
  • 09-05-2021
  • Mathematics
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solve this question ​

solve this question class=

Respuesta :

Аноним Аноним
  • 09-05-2021

Answer:

[tex] \frac{4x - 11}{2} \leqslant 3x - 3 < 4 \\ \\ = > \frac{4x - 11}{2} \leqslant 3x - 3 \: and \: 3x - 3 < 4 \\ \\ < = > 4x - 11 \leqslant 6x - 6 \: \: and \: \: 3x < 7 \\ \\ < = > 2x \geqslant - 5 \: \: and \: \: x < \frac{7}{3} \\ \\ < = > \frac{ - 5}{2} \leqslant x < \frac{7}{3} [/tex]

=> the greatest integer is 2

the smallest integer is -2

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