Answer:
[tex](2,-6)[/tex]
Step-by-step explanation:
[tex]x^2-4x+y+10=0[/tex]
[tex]y=x^2+4x-10[/tex]
[tex]y=-(x^2-4x)-10[/tex]
[tex]=-(x^2-4x+4)-10+4[/tex]
[tex]=-(x-2)^2-6[/tex]
[tex]y=-(x-2)^2+(-6)[/tex]
[tex]h=2 ~and~ k=-6[/tex]
So, vertex → (2,-6)
[tex]------------[/tex]
hope it helps..
have a great day!!
