chnlee007 chnlee007
  • 06-05-2021
  • Mathematics
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Finding the missing length

Finding the missing length class=

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Аноним Аноним
  • 06-05-2021

[tex] \huge\colorbox{black}{ \color{white}{ANSWER}}[/tex]

we know,

[tex]\mathfrak{\hookrightarrow { area = \dfrac{1}{2} \times (a + b) \times h }}[/tex]

where,

  • a = 2 cm
  • b = 5 cm
  • area = 28 cm²

So,

[tex] \hookrightarrow \mathcal{28 = \dfrac{1}{2} \times (5 + 2) \times h}[/tex]

[tex]\hookrightarrow \mathcal{28 \times 2 = 7 \times h}[/tex]

[tex]\hookrightarrow \mathcal{ \dfrac{56}{7} = h}[/tex]

[tex]\hookrightarrow \mathcal{h = 8}[/tex]

so, missing lenght = 8 cm

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