Answer:
26.5 g
Explanation:
First we convert 100.0 mL to L:
- 100.0 mL / 1000 = 0.100 L
Now we calculate how many moles of sodium carbonate are needed, using the definition of molarity:
- Molarity = moles / liters
- moles = molarity * liters
- 2.5 M * 0.100 L = 0.25 mol
Finally we convert 0.25 moles of sodium carbonate into grams, using its molar mass:
- 0.25 mol * 106 g/mol = 26.5 g
