marianaxd2004oynzl5
marianaxd2004oynzl5 marianaxd2004oynzl5
  • 07-04-2021
  • Mathematics
contestada

Four times a first number decreased by a second number is 19. The first number increased by four times the second number is −8. Find the numbers.

Respuesta :

ezioassasin55
ezioassasin55 ezioassasin55
  • 07-04-2021

Answer:

a = 4

b = -3

Step-by-step explanation:

Let a and b be the two numbers.

According to question,

4a - b = 19........(i)

And,

a + 4b = -8........(ii)

From (i),

4a - b = 19

or, b = 4a - 19

Replacing b in (ii),

a + 4(4a - 19) = -8

a + 16a - 76 = -8

17a = -8 + 76

17a = 68

a = 68/17

a = 4

And,

b = 4a - 19

= 4 x 4 - 19

= 16 - 19

= -3

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