Answer:
[tex]4\sqrt{2}[/tex]
Step-by-step explanation:
Use the distance equation
[tex]\sqrt{(x1-x2)^2+(y1-y2)^2}[/tex]
insert values (5,-2)=(x1,y1) and (1,2)=(x2,y2)
[tex]\sqrt{(5-1)^2+((-2)-2)^2}[/tex]
[tex]\sqrt{16+16}[/tex]
[tex]4\sqrt{2}[/tex]
Hope that helps :)
