Answer:
4x + 6
Step-by-step explanation:
[tex] \dfrac{x}{x^2 + 3x + 2} + \dfrac{3}{x + 1} = [/tex]
[tex] = \dfrac{x}{(x + 2)(x + 1)} + \dfrac{3}{x + 1} [/tex]
[tex] = \dfrac{x}{(x + 2)(x + 1)} + \dfrac{3(x + 2)}{(x + 1)(x + 2)} [/tex]
[tex] = \dfrac{x}{(x + 2)(x + 1)} + \dfrac{3x + 6}{(x + 1)(x + 2)} [/tex]
[tex] = \dfrac{x + 3x + 6}{(x + 2)(x + 1)} [/tex]
[tex] = \dfrac{4x + 6}{(x + 2)(x + 1)} [/tex]
Answer: 4x + 6
