rheapatel007
rheapatel007 rheapatel007
  • 08-03-2021
  • Mathematics
contestada

A rectangle has an area represented by x^2 - 4x - 12 square feet. If the length is x + 2 feet, what is the width of the rectangle?

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paquelau
paquelau paquelau
  • 08-03-2021

Answer: Since x2=6, the width of the rectangle is x-6.

Explanation: factor x^2-4x-12.

given that length=x+2 and area of rectangle = length * width

all you have to do is find the width

there are several way to do this, here is one:

Since one factor of x^2-4x-12 is x+2, x1=-2 is a solution to x62-4x-12=0 so in order to find the other solution, you can use the sum and product properties.

x1*x2= -12 with x1=-2, so x2=6.

Since x2=6, the width of the rectangle is x-6.

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