Answer:
- [tex]\frac{8}{7}[/tex] tanx
Step-by-step explanation:
Using the identities
secx = [tex]\frac{1}{cosx}[/tex] , cscx = [tex]\frac{1}{sinx}[/tex] , tanx = [tex]\frac{sinx}{cosx}[/tex]
Given
[tex]\frac{8secx}{-7cscx}[/tex]
= [tex]\frac{\frac{8}{cosx} }{\frac{-7}{sinx} }[/tex] ← multiply numerator/ denominator by sinx
= [tex]\frac{8\frac{sinx}{cosx} }{-7}[/tex]
= - [tex]\frac{8}{7}[/tex] tanx
