Step-by-step explanation:
Given
[tex] \frac{1 - sinx}{cosx} + \frac{cosx}{1 - sinx} \\ = \frac{(1 - sinx)^{2} + cos^{2}x }{cosx(1 - sinx)} \\ = \frac{1 - 2sinx + sin ^{2}x + cos {}^{2}x}{cosx(1 - sinx)} \\ = \frac{2 - 2sinx}{cosx(1 - sinx)} \\ = \frac{2(1 - sinx)}{cosx(1 - sinx)} \\ = \frac{2}{cosx} \\ = 2secx[/tex]
Hope it will help :)❤
