kobsdamaster
kobsdamaster
09-11-2016
Mathematics
contestada
parallel of y=8x-1 through (-6,2)
Respuesta :
Panoyin
Panoyin
10-11-2016
y - y₁ = m(x - x₁)
y - 2 = 8[x - (-6)]
y - 2 = 8(x + 6)
y - 2 = 8(x) + 8(6)
y - 2 = 8x + 48
+ 2 + 2
y = 8x + 50
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