Answer:
[tex]Solution,\\The ~vertex~ of~parabola~y=a(x-h)^2+k is (h,k)Given ~equation~of~parabola~is:\\y=3x^2-6x+7\\or, y = 3x^2 -6x^2+3+7-3\\or, y = 3(x^2-2x^2+1)+4\\or, y = 3(x-1)^2+4\\Compairing ~with ~y = a(x-h)^2+k,\\h = 1 ~and~ k=4.\\So,~the~required~vertex~is~(1,4).[/tex]
