Answer:
the heat given off is 75 J.
Explanation:
Given;
latent heat of fusion of lead, L= 25 J/g
mass of liquid lead, m = 3.0g
The heat given off is calculated as;
H = Lm
Where;
H is the quantity of heat given off
H = 25 x 3
H = 75 J.
Therefore, the heat given off is 75 J.
