Answer:
[tex]F_x=43.30\ N[/tex]
Step-by-step explanation:
Given that,
Force, F = 50 pounds
It is directed at 30° from the horizontal.
The force will be given by :
[tex]F_x=F\cos\theta\\\\=50\times \cos(30)\\\\=43.30\ N[/tex]
So, the required force is 43.30 N.
