Answer:
Step-by-step explanation:
DE║AC ⇒ From Thales: [tex]\dfrac{BD}{BE}=\dfrac{DA}{EC}[/tex]
Therefore:
[tex]\dfrac{10-x}{3}=\dfrac{x}2\\\\2(10-x)=3x\\\\20-2x=3x\\\\20=5x\\\\x=4[/tex]
