Answer:
30.6 L
Explanation:
Given data:
Number of molecules of nitrogen = 8.23×10²³ molecules
Volume occupy at STP = ?
Solution:
Standard temperature = 273.15 K
Standard pressure = 1 atm
One mole of any substance at STP occupy 22.4 L volume.
Number of moles of nitrogen:
1 mole contain 6.022×10²³ molecules.
8.23×10²³ molecules × 1mol / 6.022×10²³ molecules
1.37 mol
Volume of nitrogen:
1.37 mol × 22.4 L / 1 mol
30.6 L
