Answer:
V₂ = 283.15 L
Explanation:
The temperature must be in kelvin scale. We will convert the degree celsius into kelvin and then solve the equation for V₂.
T₁ = 23°C (23+273.15 = 296.15 K)
T₂ = 16°C (16+273.15 = 289.15 K)
Now we will calculate the value of V₂
290 L / 296.15 K = V₂ / 289.15 K
V₂ = 290 L × 289.15 K / 296.15 K
V₂ = 83853.5 L.K /296.15 K
V₂ = 283.15 L
