Answer:
-2
Step-by-step explanation:
Given equation is x²+px+1=0
comparing the equation with ax²+bx+c=0
then a=1,b=p,c=1
let the roots one root of the equation be A then
by question, another root is A².
we know
A(ALPHA)+A²(beta)=-b/a
A+A²=-p/1
A+A²=-p......1
again
A*A²=c/a
A³=1/1
A³=1
A=1
Now,
substituting A=1 in equation 1
1+1²=-p
2=-p
Therefore p=-2.
