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10-01-2021
Chemistry

contestada

the value of ΔE for a system that performs 13KJ of work on its surroundings and loses 9KJ of heat is ??

Respuesta :

11-01-2021

Answer:

ΔE = -22 KJ

Explanation:

Given data:

Work done = 13 KJ

Heat lose = 9 KJ (exothermic process)

ΔE = ?

Solution:

Formula:

ΔE = q + w

ΔE = - 9KJ + (-13 KJ) (work is done by the system on surrounding that's why we add negative sign)

ΔE = -22 KJ

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