Answer:
Following are the solution to this question:
Explanation:
[tex]\to \Sigma F_x = ma_x \\\\\to 3200 t^2 -440 (9.81) (\frac{8}{17}) = 440 (a) \\\\\to 3200 t^2 -2031.24 = 440 (a)\\\\\to a= 7.27t^2 -4.616\\\\\to dv=a.dt \\\\\to \int^{v}_{2} dv = \int^{2}_{0} (7.27t^2 -4.616) dt\\\\\to v-2 = 7.27 \frac{t^3}{3} - 4.616 t^{2}_{0}\\\\\to v-2 = 7.27 \frac{2^3}{3} - 4.616 {2} \\\\\to v-2 = 10.154\\\\\to v= 12.154 \ \frac{m}{s}\\[/tex]
