Given:
Two points are N(-1,-11) and P(-1,-3).
To find:
The value of NP.
Solution:
Distance formula:
[tex]D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]
Two points are N(-1,-11) and P(-1,-3). Using distance formula, we get
[tex]D=\sqrt{(-1-(-1))^2+(-3-(-11))^2}[/tex]
[tex]D=\sqrt{(-1+1)^2+(-3+11)^2}[/tex]
[tex]D=\sqrt{(0)^2+(8)^2}[/tex]
On further simplification, we get
[tex]D=\sqrt{0+64}[/tex]
[tex]D=\sqrt{64}[/tex]
[tex]D=8[/tex]
Therefore, the value of NP is 8 units.
