eiribarren24
eiribarren24 eiribarren24
  • 09-01-2021
  • Mathematics
contestada

Find the 14th term of the geometric sequence below. Leave your answer in fraction form if necessary.
64,-32,16,-8

Respuesta :

kritika3375
kritika3375 kritika3375
  • 09-01-2021

Step-by-step explanation:

First term (a) = 64 = t1

Second term (t2) = -32

Common ratio (r) = t2/ t1 = -32 / 64 = - 1/2

Now

Tn =

[tex]a {r}^{n - 1} [/tex]

[tex]t14 = 64 \: ( - \frac{1}{2}) ^{14 - 1} [/tex]

[tex] = 64 \: ( - \frac{1}{2} ) {}^{13} [/tex]

= - 64 * 1 / 8192

= - 1/128

Hope it will help :)❤

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