9514 1404 393
Answer:
x = {-0.2, 6.2}
Step-by-step explanation:
The values that go into the quadratic formula are a = 1, b = -6, c = -1.
[tex]x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}=\dfrac{-(-6)\pm\sqrt{(-6)^2-4(1)(-1)}}{2(1)}\\\\=\dfrac{6\pm\sqrt{40}}{2}=3\pm\sqrt{10}\\\\\boxed{x\in\{-0.2,\ 6.2\}}[/tex]
