Answer:
0.0659M
Explanation:
...5,15g of Fe(NO₃)₃ is dissolved...
Molar concentration is the amount of moles presents in 1L of solution. To solve this question we need to find the moles of iron nitrate, Fe(NO₃)₃ present in the 323mL of solution:
Moles Fe(NO₃)₃ -Molar mass 241.86g/mol-:
5.15g Fe(NO₃)₃ * (1mol / 241.86g) = 0.0213moles Fe(NO₃)₃
And molarity is:
0.0213moles Fe(NO₃)₃ / 0.323L = 0.0659M
