Answer:
Jug B can hold 2340 ml.
Step-by-step explanation:
Given
The amount in Jug A = 1800ml
To determine
How much does jug B hold?
Give that the Jug B holds 3/10 more, i.e.
[tex]\frac{3}{10}\times \:1800=540[/tex]
Thus,
The total amount in Jug B = 540+1800
= 2340 ml
Therefore, Jug B can hold 2340 ml.
