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An object decelerates from 25.0 m / s to 5.0 m / s in a time of 4.0 s. It has a mass of 50 kg. What is the resultant force on the object?​

Respuesta :

HoneyLemon14

Answer:

10 N

Explanation:

Force = Mass÷Acceleration

F= 50 ÷ 5

= 10 N

______________________

Acceleration =

[tex] \frac{5 - 25}{4 } [/tex]

= 5m/s2

Cricetus

The resultant force will be "10 N".

Given:

  • Mass, m = 50 kg
  • Acceleration, a = 5.0 m/s
  • Time, t = 4.0 s

As we know,

The acceleration will be:

= [tex]\frac{5-25}{4}[/tex]

= [tex]5 \ m/s^2[/tex]

hence,

The force will be:

→ [tex]F = \frac{m}{a}[/tex]

By substituting the values, we get

      [tex]= \frac{50}{5}[/tex]

      [tex]= 10 \ N[/tex]

Thus the above response is right.  

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