Answer:
x = 21.7 cm
Explanation:
The energy stored in the spring is given by :
[tex]U=\dfrac{1}{2}kx^2[/tex]
Where
k is spring constant
x is compression or elongation in the spring
Let us assume that the spring constant of the spring is 6740 N/m.
We can find x by using above formula.
[tex]x=\sqrt{\dfrac{2U}{k}} \\\\x=\sqrt{\dfrac{2\times 160}{6740}} \\\\x=0.217\ m[/tex]
or
x = 21.7 cm
Hence, to store 160 J of energy, it must compress 21.7 cm.
